1959 NBA Finals
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Dates | April 4–9 | |||||||||
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Western Finals | Lakers defeated Hawks, 4–2 | |||||||||
The 1959 NBA Finals, then known as the 1959 NBA World Championship Series, was the
Boston Celtics. It was Boston's third trip to the NBA Finals and Minneapolis's sixth. The Boston Celtics swept the Lakers 4–0. That was the start of the skein of the Celtics' eight consecutive championships, from 1959 to 1966. To date, this is the most recent time that an NBA team from Minnesota appeared in an NBA Finals, as well as the first of two times in NBA history that a team with a losing record made the NBA Finals (the other was in 1981
).
Series summary
Game | Date | Home team | Result | Road team |
---|---|---|---|---|
Game 1 | April 4 | Boston Celtics | 118–115 (1–0) | Minneapolis Lakers |
Game 2 | April 5 | Boston Celtics | 128–108 (2–0) | Minneapolis Lakers |
Game 3 | April 7 | Minneapolis Lakers | 110–123 (0–3) | Boston Celtics |
Game 4 | April 9 | Minneapolis Lakers | 113–118 (0–4) | Boston Celtics |
Celtics win series 4–0
Team rosters
Boston Celtics
- 6 Russell
- 14 Cousy
- 15 Heinsohn
- 16 Swain
- 17 Conley
- 18 Loscutoff
- 21 Sharman
- 23 Ramsey
- 24 S. Jones
- 25 K. Jones
- 29 Tsioropoulos
- Head coach: Auerbach
Minneapolis Lakers
- 14 Foust
- 16 Garmaker
- 19 Mikkelsen
- 21 Leonard
- 22 Baylor
- 23 Ellis
- 30 Hamilton
- 32 Krebs
- 33 Hundley
- 50 Fleming
- 69 Lindahl
- Coach Kundla