Kruskal's tree theorem

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In mathematics, Kruskal's tree theorem states that the set of finite trees over a well-quasi-ordered set of labels is itself well-quasi-ordered under homeomorphic embedding.

History

The

arithmetical transfinite recursion
).

In 2004, the result was generalized from trees to graphs as the Robertson–Seymour theorem, a result that has also proved important in reverse mathematics and leads to the even-faster-growing SSCG function, which dwarfs . A finitary application of the theorem gives the existence of the fast-growing TREE function.

Statement

The version given here is that proven by Nash-Williams; Kruskal's formulation is somewhat stronger. All trees we consider are finite.

Given a tree T with a

root
, and given vertices v, w, call w a successor of v if the unique path from the root to w contains v, and call w an immediate successor of v if additionally the path from v to w contains no other vertex.

Take X to be a partially ordered set. If T1, T2 are rooted trees with vertices labeled in X, we say that T1 is inf-embeddable in T2 and write if there is an

injective map
F from the vertices of T1 to the vertices of T2 such that:

  • For all vertices v of T1, the label of v precedes the label of ;
  • If w is any successor of v in T1, then is a successor of ; and
  • If w1, w2 are any two distinct immediate successors of v, then the path from to in T2 contains .

Kruskal's tree theorem then states:

If X is well-quasi-ordered, then the set of rooted trees with labels in X is well-quasi-ordered under the inf-embeddable order defined above. (That is to say, given any infinite sequence T1, T2, … of rooted trees labeled in X, there is some so that .)

Friedman's work

For a

ATR0,[1] thus giving the first example of a predicative result with a provably impredicative proof.[2] This case of the theorem is still provable by Π1
1
-CA0, but by adding a "gap condition"[3] to the definition of the order on trees above, he found a natural variation of the theorem unprovable in this system.[4][5]
Much later, the Robertson–Seymour theorem would give another theorem unprovable by Π1
1
-CA0.

proof-theoretic ordinal of the theorem equaling the small Veblen ordinal (sometimes confused with the smaller Ackermann ordinal).[6]

Weak tree function

Suppose that is the statement:

There is some m such that if T1, ..., Tm is a finite sequence of unlabeled rooted trees where Ti has vertices, then for some .

All the statements are true as a consequence of Kruskal's theorem and Kőnig's lemma. For each n, Peano arithmetic can prove that is true, but Peano arithmetic cannot prove the statement " is true for all n".[7] Moreover, the length of the shortest proof of in Peano arithmetic grows phenomenally fast as a function of n, far faster than any primitive recursive function or the Ackermann function, for example.[citation needed] The least m for which holds similarly grows extremely quickly with n.

Define , the weak tree function, as the largest m so that we have the following:

There is a sequence T1, ..., Tm of unlabeled rooted trees, where each Ti has at most vertices, such that does not hold for any .

It is known that , , (about 844 trillion), (where is Graham's number), and (where the argument specifies the number of labels; see below) is larger than

To differentiate the two functions, "TREE" (with all caps) is the big TREE function, and "tree" (with all letters in lowercase) is the weak tree function.

TREE function

Sequence of trees where each node is colored either green, red, blue
A sequence of rooted trees labelled from a set of 3 labels (blue < red < green). The nth tree in the sequence contains at most n vertices, and no tree is inf-embeddable within any later tree in the sequence. TREE(3) is defined to be the longest possible length of such a sequence.

By incorporating labels, Friedman defined a far faster-growing function.[8] For a positive integer n, take [a] to be the largest m so that we have the following:

There is a sequence T1, ..., Tm of rooted trees labelled from a set of n labels, where each Ti has at most i vertices, such that does not hold for any .

The TREE sequence begins , , then suddenly, explodes to a value that is so big that many other "large" combinatorial constants, such as Friedman's , , and

lower bound
for , and, hence, an extremely weak lower bound for , is .[c][9] Graham's number, for example, is much smaller than the lower bound . It is approximately , where is Graham's function.

See also

Notes

^ a Friedman originally denoted this function by TR[n].
^ b n(k) is defined as the length of the longest possible sequence that can be constructed with a k-letter alphabet such that no block of letters xi,...,x2i is a subsequence of any later block xj,...,x2j.[10] .
Ackermann's function
defined as: A(1, n) = 2n, A(k+1, 1) = A(k, 1), A(k+1, n+1) = A(k, A(k+1, n)).

References

Citations

  1. ^ Simpson 1985, Theorem 1.8
  2. ^ Friedman 2002, p. 60
  3. ^ Simpson 1985, Definition 4.1
  4. ^ Simpson 1985, Theorem 5.14
  5. ^ Marcone 2001, p. 8–9
  6. ^ Rathjen & Weiermann 1993.
  7. ^ Smith 1985, p. 120
  8. ^ Friedman, Harvey (28 March 2006), "273:Sigma01/optimal/size", Ohio State University Department of Maths, retrieved 8 August 2017
  9. ^ Friedman, Harvey M. (1 June 2000), "Enormous Integers In Real Life" (PDF), Ohio State University, retrieved 8 August 2017
  10. ^ Friedman, Harvey M. (8 October 1998), "Long Finite Sequences" (PDF), Ohio State University Department of Mathematics, pp. 5, 48 (Thm.6.8), retrieved 8 August 2017

Bibliography