Statute of the Council of Europe

Source: Wikipedia, the free encyclopedia.
(Redirected from
Treaty of London (1949)
)

Statute of the Council of Europe
TypeMultilateral treaty
Signed5 May 1949 (1949-05-05)
LocationLondon, England, United Kingdom
Original
signatories
Belgium, Denmark, France, Ireland, Italy, Luxembourg, Netherlands, Norway, Sweden, United Kingdom
RatifiersBelgium, Denmark, France, Ireland, Italy, Luxembourg, Netherlands, Norway, Sweden, United Kingdom

The Statute of the Council of Europe (also known as the Treaty of London (1949)), signed on 5 May 1949, brought into existence the

Committee of Ministers and the Parliamentary Assembly
.

The original signatories in 1949 were Belgium, Denmark, France, Ireland, Italy, Luxembourg, Netherlands, Norway, Sweden and the United Kingdom, though the Statute has now been signed and ratified by 46 European states. Only Belarus, Kazakhstan, and the Vatican City (the Holy See) are not members, while Russia was expelled from the Council of Europe on 16 March 2022 after 26 years of membership - the only country ever to be expelled in the history of the Organisation - because of its aggression against Ukraine and invasion of a fellow member state, regarded as an extreme violation of the Statute.[2]

The treaty was registered with the United Nations on 11 April 1951 with Treaty Number I:1168, vol.87, page 103.[1][2]

See also

References

  1. ^ "UN Cumulative Treaty Index" (PDF). Archived (PDF) from the original on 19 May 2014. Retrieved 12 September 2013.
  2. ^ "Statute of the Council of Europe as registered with the UN" (PDF). Archived (PDF) from the original on 19 May 2014. Retrieved 14 September 2013.

External links