1990 Atlantic 10 Conference baseball tournament

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1990 Atlantic 10 Conference
baseball tournament
Teams4
FormatFour-team
Boyertown, PA
ChampionsRutgers (4th title)
Winning coachFred Hill (3rd title)
MVPPaul Prosser (West Virginia)

The 1990

double elimination tournament featured the top two regular-season finishers from both of the league's divisions. East top seed Rutgers defeated West Virginia in the title game to win the tournament for the fourth time, earning the Atlantic 10's automatic bid to the 1990 NCAA tournament.[1]

Seeding and format

Each division's top teams, based on winning percentage in the 16-game regular season schedule, qualified for the field. In the opening round of the four-team double-elimination format, the East Division champion played the West Division runner-up, and vice versa.

Team W L Pct. GB Seed
East Division
Rutgers 14 2 .875
1E
Massachusetts 12 4 .750
2
2E
Rhode Island 6 10 .375
8
Temple 5 11 .313
9
Saint Joseph's 3 13 .188
9
West Division
George Washington
13 3 .813
1W
West Virginia 12 4 .750
1
2W
St. Bonaventure 7 9 .438
6
Penn State 6 10 .375
7
Duquesne
2 14 .125
11

Bracket

First roundSemi-finalsFinals
1E
Massachusetts
13
1ERutgers26
2WWest Virginia114
Lower round 1Lower final
2EMassachusetts1
2WWest Virginia112WWest Virginia9
1WGeorge Washington10

All-Tournament

West Virginia's Paul Prosser was named Most Outstanding Player, while Rutgers's Darrin Kotch was named Most Outstanding Pitcher.

References

  1. ^ "2014 Atlantic 10 Baseball Record Book" (PDF). Atlantic10.com. Archived from the original (PDF) on May 19, 2014. Retrieved July 15, 2014.