1849 French legislative election in Réunion
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Elections to the French National Assembly were held in Réunion on 30 September 1849 as part of the wider French elections, with a second round on 21 October. The territory elected two seats, with voters able to cast two votes.[1] The seats were won by Charles Ogé Barbaroux and Jean-Baptiste de Greslan.
Results
| Candidate | First round | Second round | ||
|---|---|---|---|---|
| Votes | % | Votes | % | |
| Jean-Baptiste de Greslan | 3,340 | 32.31 | 5,297 | 33.84 |
| Charles Ogé Barbaroux | 3,212 | 31.08 | 5,398 | 34.49 |
| Sully Brunet | 2,739 | 26.50 | 3,911 | 24.99 |
| Charles Fery d'Esclands | 1,045 | 10.11 | ||
| Timagène Houat | 1,045 | 6.68 | ||
| Total | 10,336 | 100.00 | 15,651 | 100.00 |
| Total votes | 6,405 | – | 9,186 | – |
| Registered voters/turnout | 36,723 | 17.44 | 34,810 | 26.39 |
| Source: Compte-rendu des séances de l'Assemblée nationale | ||||
References
- Bernhard Vogel, Dieter Nohlen& Klaus Landfried (1978) Die Wahl der Parlamente: Band II: Afrika, Zweiter Halbband, p1603
