1870 Rhode Island gubernatorial election
Appearance
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Elections in Rhode Island |
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The 1870 Rhode Island gubernatorial election took place on April 6, 1870 in order to elect the governor of Rhode Island.[1] Republican candidate and incumbent governor Seth Padelford won his second one-year term as governor[2] over Democratic candidate Lyman Pierce.[3]
Candidates
Republican Party
- Lieutenant Governor of Rhode Island from 1863 to 1865 under James Y. Smith.[2]
Democratic Party
- Lyman Pierce, the Democratic nominee, had been nominated in the previous year's election to become the governor of Rhode Island.[4]
Election
Statewide
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Seth Padelford | 10,337 | 62.15 | |
Democratic | Lyman Pierce | 6,295 | 37.85 | |
Total votes | 16,632 | 100.00 | ||
Republican hold |
References
- ^ ISBN 9780786456468.
- ^ a b "Seth Padelford". National Governors Association. 1 January 2019. Retrieved 27 March 2024.
- ^ "Our State Election". The Bristol Phoenix. 2 April 1870. Retrieved 27 March 2024 – via NewspaperArchive.com.
- Newspapers.com.