1964 United States presidential election in Rhode Island
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Johnson 50–60% 60–70% 70–80% 80–90% 90–100%
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Elections in Rhode Island |
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The 1964 United States presidential election in Rhode Island took place on November 3, 1964, as part of the 1964 United States presidential election, which was held throughout all 50 states and D.C. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island voted overwhelmingly for the Democratic nominee, incumbent President Lyndon B. Johnson of Texas, over the Republican nominee, Senator Barry Goldwater of Arizona. Johnson ran with Senator Hubert H. Humphrey of Minnesota, while Goldwater's running mate was Congressman William E. Miller of New York.
Johnson carried Rhode Island in a landslide, taking 80.87% of the vote to Goldwater's 19.13%,[1] a Democratic victory margin of 61.74%. This made Rhode Island Lyndon Johnson's strongest state in the nation: even in the midst of a massive nationwide Democratic landslide, Rhode Island weighed in as 39% more Democratic than the national average during the 1964 election.[2]
The staunch conservative Goldwater was widely seen in the
Results
| Presidential candidate | Party | Home state | Popular vote | Electoral vote |
Running mate | |||
|---|---|---|---|---|---|---|---|---|
| Count | Percentage | Vice-presidential candidate | Home state | Electoral vote | ||||
| Lyndon B. Johnson | Democratic | Texas | 315,463 | 80.87% | 4 | Hubert Humphrey | Minnesota | 4 |
| Barry Goldwater | Republican | Arizona | 74,615 | 19.13% | 0 | William E. Miller | New York | 0 |
| Total | 390,078 | 100% | 4 | 4 | ||||
| Needed to win | 270 | 270 | ||||||
By county
| County | Lyndon B. Johnson Democratic |
Barry Goldwater Republican |
Various candidates Other parties |
Margin | Total votes cast | ||||
|---|---|---|---|---|---|---|---|---|---|
| # | % | # | % | # | % | # | % | ||
| Bristol | 14,306 | 76.21% | 4,466 | 23.79% | 0 | 0.00% | 9,840 | 52.42% | 18,772 |
| Kent | 44,476 | 78.34% | 12,297 | 21.66% | 0 | 0.00% | 32,179 | 56.68% | 56,773 |
| Newport | 19,782 | 73.65% | 7,078 | 26.35% | 0 | 0.00% | 12,704 | 47.30% | 26,860 |
| Providence | 219,465 | 83.48% | 43,432 | 16.52% | 0 | 0.00% | 176,033 | 66.96% | 262,897 |
| Washington | 17,434 | 70.37% | 7,342 | 29.63% | 0 | 0.00% | 10,092 | 40.74% | 24,776 |
| Totals | 315,463 | 80.87% | 74,615 | 19.13% | 13 | 0.00% | 240,848 | 61.74% | 390,091 |
Counties that flipped from Republican to Democratic
Analysis
Johnson swept all five counties in Rhode Island with over 70% of the vote. In Providence County, the most populated county, home to the state's capital and largest city, Providence, Johnson took 83.5% of the vote.[1] Washington County voted Democratic for the first time since 1852. This was the strongest showing ever for a Democratic presidential candidate in Providence County and the strongest performance of any candidate of any party in any county in Rhode Island. Johnson's 80.87% remains the highest vote share percentage any presidential candidate of either party has ever received in Rhode Island,[2] and his 61.74% victory margin remains the widest margin by which any candidate of either party has ever won the state. Additionally, Johnson's victory, alongside Goldwater's victory in Mississppi marked the last time a Presidential nominee won over 80% of the vote in a state.
See also
References
- ^ a b David Leip’s Atlas of U.S. Presidential Elections; 1964 Presidential General Election Data Graphs – Rhode Island
- ^ a b Counting the Votes; Rhode Island Archived 2017-01-11 at the Wayback Machine
- ^ ISBN 1510702369.
- ISBN 162157458X.
- ISSN 0362-4331. Retrieved November 15, 2020.
