1894 United States House of Representatives election in Wyoming

1894 United States House of Representatives election in Wyoming
	County results; Mondell: 40–50% 50–60% 60–70% ; Coffeen: 30–40% ; No Data
U.S. Representative before election; Henry A. Coffeen; Democratic	Elected U.S. Representative ; Frank Wheeler Mondell; Republican

The Wyoming United States House election for 1894 was held on November 6, 1894. Republican Frank Wheeler Mondell defeated Democratic incumbent Henry A. Coffeen and Populist Shakespeare E. Sealey with 52.64% of the vote making Coffeen the second incumbent Representative from Wyoming to lose reelection.

Results

United States House of Representatives election in Wyoming, 1894^[1]
Party		Candidate	Votes	%
	Republican	Frank Wheeler Mondell	10,068	52.64%
	Democratic	Henry A. Coffeen (inc.)	6,152	32.17%
	Populist	Shakespeare E. Sealey	2,906	15.19%
Total votes			19,126	100%

References

^ "United States House of Representatives election in Wyoming, 1894".

[1] "United States House of Representatives election in Wyoming, 1894".

[1]