1945 U.S. National Championships – Women's singles

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Women's singles
1945 U.S. National Championships
Final
ChampionUnited States Sarah Palfrey Cooke[1]
Runner-upUnited States Pauline Betz
Score3–6, 8–6, 6–4
Details
Draw32
Seeds8
Events
Singles men women
Doubles men women
← 1944 ·
U.S. National Championships
· 1946 →

Second-seeded Sarah Palfrey Cooke defeated first-seeded Pauline Betz 3–6, 8–6, 6–4 in the final to win the women's singles tennis title at the 1945 U.S. National Championships.[1]

Seeds

The eight seeded U.S. players are listed below. Sarah Palfrey Cooke is the champion; others show in brackets the round in which they were eliminated.[2][3]

  1. United States Pauline Betz (finalist)
  2. United States Sarah Palfrey Cooke (champion)
  3. United States Margaret Osborne (quarterfinals)
  4. United States Louise Brough (semifinals)
  5. United States Patricia Todd (quarterfinals)
  6. United States Mary Arnold (quarterfinals)
  7. Dorothy Bundy
    (quarterfinals)
  8. United States Doris Hart (semifinals)

One foreign player was seeded.

  1. Argentina Mary Terán de Weiss (second round)

Draw

Final eight

Quarterfinals Semifinals Finals
               
2 United States Sarah Palfrey Cooke 6 6
7
Dorothy Bundy
3 4
2 United States Sarah Palfrey Cooke 6 6
4 United States Louise Brough 3 4
4 United States Louise Brough 6 6
5 United States Patricia Todd 2 4
2 United States Sarah Palfrey Cooke 3 8 6
1 United States Pauline Betz 6 6 4
1 United States Pauline Betz 0 6 6
6 United States Mary Arnold 6 4 4
1 United States Pauline Betz 6 6
8 United States Doris Hart 3 2
3 United States Margaret Osborne 2 3
8 United States Doris Hart 6 6

References

  1. ^ .
  2. ^ Official Tennis Guide 1946. [New York City]: A.S. Barnes and Company. 1946. pp. 37–39, 41.
  3. The Milwaukee Sentinel
    . AP. August 24, 1945. p. 5 (part 2).
Preceded by Grand Slam women's singles Succeeded by