1956 U.S. National Championships – Women's singles

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Women's singles
1956 U.S. National Championships
Final
ChampionUnited States Shirley Fry[1]
Runner-upUnited States Althea Gibson[1]
Score6–3, 6–4
Details
Seeds8
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1955 ·
U.S. National Championships
· 1957 →

First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]

Seeds

The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.

  1. United States Shirley Fry (champion)
  2. United States Althea Gibson (finalist)
  3. United States Louise Brough (quarterfinals)
  4. Dorothy Knode
    (quarterfinals)
  5. Margaret duPont
    (quarterfinals)
  6. Shirley Bloomer
    (semifinals)
  7. United States Betty Pratt (semifinals)
  8. United States Darlene Hard (quarterfinals)

Draw

Key

  • Q =
    Qualifier
  • WC =
    Wild card
  • LL = Lucky loser
  • r =
    Retired

Final eight

Quarterfinals Semifinals Finals
               
1 United States Shirley Fry 6 4 6
5
Margaret duPont
2 6 3
1 United States Shirley Fry 6 6
6
Shirley Bloomer
4 4
6
Shirley Bloomer
6 6
3 United States Louise Brough 3 3
1 United States Shirley Fry 6 6
2 United States Althea Gibson 3 4
4
Dorothy Knode
6 0 2
7 United States Betty Pratt 4 6 6
8 United States Betty Pratt 1 8
2 United States Althea Gibson 6 10
8 United States Darlene Hard 7 1
2 United States Althea Gibson 9 6

References

  1. ^ .
  2. ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
  3. ^ "National Tennis Championships Opens Today". The Free Lance–Star. AP. August 31, 1956. p. 12.
Preceded by Grand Slam women's singles Succeeded by