Seymourville, West Virginia

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Coordinates: 39°03′25″N 79°06′32″W / 39.05694°N 79.10889°W / 39.05694; -79.10889
Source: Wikipedia, the free encyclopedia.

Seymourville, West Virginia
UTC-4 (EDT)
Area code(s)304 & 681
GNIS feature ID1555594[1]

Seymourville is an unincorporated community in Grant County, West Virginia, United States. Seymourville is 4.5 miles (7.2 km) north of Petersburg.

References

  1. ^ a b U.S. Geological Survey Geographic Names Information System: Seymourville, West Virginia


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