Talk:Ekman transport

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Question to those in the know: if Earth rotated much more slowly would ocean water still flow at 90 degrees angle from the wind? Is the angle steady hard and immediate 90 degrees clockwise as soon as water moves south of the equator but 90 degrees CCW when a smidgeon north of the equator? It is not 90 degrees at all is it? maybe it approaches 90 degrees or the forces on the water is at 90 degrees to the wind but the flow of water cant be discongruous at the equator.----

I have erased this sentence that I find to be false. The reason for the Chile-Peru upwelling to occur is not due to El-Nino.

An example is the coast of

mean some in some years, fishing is good, and others it is not.

Where are they?? Besides helping with Verifiability,this is an article about a phenomenom which the vast majority of people ( aside from those who study oceanography ) don't know about.. some references would be handy for them as well as for students doing projects etc. Kotare 09:17, 27 April 2007 (UTC)[reply]

I have removed the 'reqdiagram' tag which was placed before the current diagram was added. If anyone wasnts a better picture, please replace it. Egmason (talk) 02:50, 20 November 2013 (UTC)[reply]

The line describing Ekman pumping and suction is incorrect - it is the other way round - Ekman pumping is a result of Ekman divergence. — Preceding unsigned comment added by 137.158.153.203 (talk) 12:31, 29 July 2014 (UTC)[reply]

Why are there no numbers at all, not even very approximate, e.g. for depth and velocity of Ekman transport away from the equator in the mid-Pacific, mid-Atlantic, and mid-Indian? Is the depth 1 m, 10 m, 100 m, 1 km? And is the velocity 1 m per second, per day, per year? Vaughan Pratt (talk) 16:43, 5 August 2014 (UTC)[reply]

I think there is an error in formula (3), since integrating over 2nd equation with respect to z should result in zero, this only happens when we integrate over z from 0 to -inf. So there is an inconsistency in the page, since we assume z to be positive in the downward direction, but use z negative in the downward direction in formula (3). — Preceding unsigned comment added by JesperPeterse (talk • contribs) 07:54, 21 April 2015 (UTC)[reply]