1939 U.S. National Championships – Women's singles

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Women's singles
1939 U.S. National Championships
Final
ChampionUnited States Alice Marble[1]
Runner-upUnited States Helen Jacobs
Score6–0, 8–10, 6–4
Details
Draw64
Seeds8
Events
Singles men women
Doubles men women
← 1938 ·
U.S. National Championships
· 1940 →

First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–0, 8–10, 6–4 in the final to win the women's singles tennis title at the 1939 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 7, through September 17, 1939 at the West Side Tennis Club in Forest Hills, Queens, New York.[1][2]

The draw consisted of 64 players of which eight were seeded.

Seeds

The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.

  1. United States Alice Marble (champion)
  2. United States Helen Jacobs (finalist)
  3. Sarah Fabyan
    (quarterfinals)
  4. Dorothy Bundy
    (quarterfinals)
  5. Gracyn Wheeler
    (first round)
  6. United States Helen Bernhard (third round)
  7. United States Dorothy Workman (third round)
  8. United States Virginia Wolfenden (semifinals)

Draw

Final eight

Quarterfinals Semifinals Finals
               
2 United States Helen Jacobs 2 6 6
United Kingdom Valerie Scott 6 2 3
2 United States Helen Jacobs 7 6
United Kingdom Kay Stammers 5 0
3
Sarah Fabyan
6 3 3
United Kingdom Kay Stammers 1 6 6
2 United States Helen Jacobs 0 10 4
1 United States Alice Marble 6 8 6
1 United States Alice Marble 6 6 6
United Kingdom Mary Hardwick 3 8 2
1 United States Alice Marble 6 6
8 United States Virginia Wolfenden 0 1
4
Dorothy Bundy
6 1 2
8 United States Virginia Wolfenden 2 6 6

References

  1. ^ .
  2. ^ "Rigs defeats Van Horn". The Advocate. Tasmania, Australia. September 19, 1939. p. 3 – via National Library of Australia.
Preceded by Grand Slam women's singles Succeeded by