Fern, Wisconsin

Coordinates: 45°50′10″N 88°23′09″W / 45.83611°N 88.38583°W / 45.83611; -88.38583
Source: Wikipedia, the free encyclopedia.

Fern, Wisconsin
FIPS code
55-25675[2]
GNIS feature ID1583200[1]

Fern is a town in Florence County, Wisconsin, United States. The population was 153 at the 2000 census.

Geography

According to the United States Census Bureau, the town has a total area of 35.2 square miles (91.1 km2), of which, 34.0 square miles (88.1 km2) of it is land and 1.2 square miles (3.0 km2) of it (3.33%) is water.

Demographics

As of the

White
, and 1.96% from two or more races.

There were 71 households, out of which 25.4% had children under the age of 18 living with them, 56.3% were married couples living together, 8.5% had a female householder with no husband present, and 32.4% were non-families. 31.0% of all households were made up of individuals, and 14.1% had someone living alone who was 65 years of age or older. The average household size was 2.15 and the average family size was 2.67.

In the town, the population was spread out, with 22.2% under the age of 18, 2.0% from 18 to 24, 21.6% from 25 to 44, 35.3% from 45 to 64, and 19.0% who were 65 years of age or older. The median age was 46 years. For every 100 females, there were 118.6 males. For every 100 females age 18 and over, there were 124.5 males.

The median income for a household in the town was $37,708, and the median income for a family was $43,125. Males had a median income of $35,625 versus $18,125 for females. The

poverty line
, including 14.3% of those under the age of eighteen and 14.8% of those 65 or over.

References

  1. ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ^ a b "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.

45°50′10″N 88°23′09″W / 45.83611°N 88.38583°W / 45.83611; -88.38583