Perceptual quantizer

${\displaystyle F_{D}=EOTF[E']=10000\left({\frac {\max[(E'^{1/m_{2}}-c_{1}),0]}{c_{2}-c_{3}\cdot E'^{1/m_{2}}}}\right)^{1/m_{1}}}$

The PQ inverse EOTF is as follows:

${\displaystyle E'=EOTF^{-1}[F_{D}]=\left({\frac {c_{1}+c_{2}\cdot Y^{m_{1}}}{1+c_{3}\cdot Y^{m_{1}}}}\right)^{m_{2}}}$

where

• ${\displaystyle E'}$ is the non-linear signal value, in the range ${\displaystyle \left[0,1\right]}$.
• ${\displaystyle F_{D}}$ is the displayed luminance in cd/m²
• ${\displaystyle Y=F_{D}/10000}$ is the normalized linear displayed value, in the range [0:1] (with ${\displaystyle Y=1}$ representing the peak luminance of 10000 cd/m²)
• ${\displaystyle m_{1}={\frac {2610}{16384}}={\frac {1305}{8192}}=0.1593017578125}$
• ${\displaystyle m_{2}=128{\frac {2523}{4096}}={\frac {2523}{32}}=78.84375}$

• ${\displaystyle c_{1}={\frac {3424}{4096}}={\frac {107}{128}}=0.8359375=c_{3}-c_{2}+1}$
• ${\displaystyle c_{2}=32{\frac {2413}{4096}}={\frac {2413}{128}}=18.8515625}$
• ${\displaystyle c_{3}=32{\frac {2392}{4096}}={\frac {2392}{128}}=18.6875}$

See also