Talk:1s Slater-type function

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I really think this page needs to be modified somewhat. At the moment, it reads more like a collage of ideas rather than a cohesive article. The naming for this article is inspired from Szabo and Ostlund pg. 153 --HappyCamper 02:01, 12 June 2007 (UTC)[reply]

Slater functions are ${\displaystyle e^{-\zeta r}}$ why one need integral of ${\displaystyle e^{-\alpha r^{2}}}$? — Preceding unsigned comment added by Nassimi (talk • contribs) 16:57, 25 April 2013 (UTC)[reply]

Good question. In fact these two integrals (one for n even and one for n odd) are irrelevant to the problem, so I will remove them from the article. Dirac66 (talk) 18:26, 25 April 2013 (UTC)[reply]

It is very good that this page includes calculations. Unfortunately only results. If anybody should be able to fill out the equations step by step with numbers so everybody can see how to do the calculation that should be very helpfull to understand how to use the equations. Thanks in advanced. — Preceding unsigned comment added by 91.97.185.40 (talk) 10:08, 15 February 2018 (UTC)[reply]