Talk:Barbu (card game)

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Must all contracts be chosen?

I've never heard of this game before. I've just read the description; and (for reasons of logic) I suspect that a crucial point is missing. The text says that the declarer decides which contract to play; and that the number of deals equals the number of deals with that declarer; and that all contracts will be played with this declarer. The logical conclusion would be that the declarer is not free to choose any contract (except for the first deal), but always must choose a contract not yet chosen.

Am I right? In that case, this information ought to be added to the text; since it is not obvious from the present formulation (and very different from many other contract games). JoergenB (talk) 20:59, 21 November 2011 (UTC)[reply]

You are correct. If you can articulate that better, please do. When I teach people to play the game, I say, "You know, like in Yahtzee," and they understand that dynamic. Morganfitzp (talk) 23:15, 21 November 2011 (UTC)[reply]

What IS the total sum?

I've found some discrepancies in the sums of points.

  1. Before presenting the contract, the text states: The total scores for all seven contracts taken together add up to zero.
  2. In the section 'Game, the text states: Once all 28 hands have been played, scores are tallied and the player with the greatest number of points wins. The scores of all players should add up to -540.....
  3. Adding the points given for each one of the seven contracts yields -69, which for a total 28 hands game would mean that the sum of the scores ought to be -276 points.

All three are given for the original, seven-type-contract game. In my own calculations, I ignored the effects of doubling and redoubling, or of non-playing a non-doubled negative contract, since in both situations, according to the description, the total points of that contract is not influenced.

What is "the truth" here - or is the gamed played with different numbers of points in different places, therefore also yielding different total scores? JoergenB (talk) 21:14, 21 November 2011 (UTC)[reply]

In the seven contracts, five are played for negative numbers of points, (as in Hearts (card game) and two are played for positive point values (as in most other card games). The total scored for each hard is as follows:
  • No Tricks: -26
  • No Hearts: -30
  • No Queens: -24
  • No King: -20
  • No Last Two: -30
  • Trumps: +65
  • Domino: +65
That's -130 for the negative contracts and +130 for the positive scoring contracts. These failed to equate zero when you looked at the article because someone made an edit that changed the point values to reflect those given in the Ravage City variation, knocking the point balance out of whack. I've corrected it and updated the references. Morganfitzp (talk) 02:08, 23 November 2011 (UTC)[reply]
Thanks, now the article is much more logical...
I'll look a bit at the language, and try to explain the "Yahtzee convention" in a way that I would have understood, if I read the article for the first time. Cheers, JoergenB (talk) 13:10, 25 November 2011 (UTC)[reply]
I guessed that when you wrote that the person to the right of the declarer deals the cards, and the person to the right of the dealer cuts them, you also meant that the dealer also is the shuffler. If this is wrong, then please correct what I wrote! JoergenB (talk) 13:26, 25 November 2011 (UTC)[reply]
Yes, that's the convention in games of the Whist family. Morganfitzp (talk) 13:26, 27 July 2012 (UTC)[reply]

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King (variant of barbu)

 – Pointer to relevant discussion elsewhere.

Please see Wikipedia:Articles for deletion/King (card game).

Short version:

WP:CFORK from a section of Barbu (card game); it's unclear to the casual observer what from that page needs to merge to the section.  — SMcCandlish ¢ 😼  05:48, 14 December 2020 (UTC)[reply
]