1910 Vermont gubernatorial election

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1910 Vermont gubernatorial election

← 1908 September 6, 1910 (1910-09-06) 1912 →
 
Nominee John A. Mead Charles D. Watson
Party Republican Democratic
Popular vote 35,263 17,425
Percentage 64.2% 31.7%

Governor before election

George H. Prouty
Republican

Elected Governor

John A. Mead
Republican

The 1910 Vermont gubernatorial election took place on September 6, 1910. Incumbent Republican

Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson
to succeed him.

Marshall J. Hapgood spent $103.76 (equivalent to $3,393 in 2023) during the campaign.[2]

Results

1910 Vermont gubernatorial election[3]
Party Candidate Votes % ±%
Republican John A. Mead 35,263 64.2
Democratic Charles D. Watson 17,425 31.7
Prohibition Edwin R. Towle 1,044 1.9
Socialist Chester E. Ordway 1,055 1.9
N/A Other 141 0.3
Total votes '54,928' '100'

References

  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. Newspapers.com
    .
  3. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.