1852 United States presidential election in Vermont
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County Results
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Elections in Vermont |
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The 1852 United States presidential election in Vermont took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for the Whig Party candidate, Winfield Scott, over the Democratic candidate, Franklin Pierce. Scott won the state by a margin of 20.8%. This would be the last election until 1916 where a Democratic candidate won more than 40% of the vote in a Vermont county.
Vermont was one of only four states to vote for Scott. The other three were neighboring Massachusetts, Kentucky, and Tennessee.
With 50.52% of the popular vote, Vermont would prove to be Scott's third strongest state after Kentucky and Tennessee.[1] It was also Scott's strong state by margin by victory.
After this election, Vermont would vote for the nominee of the Republican Party, which would be formed in 1854, for 27 consecutive elections, from 1856 through 1960—as of 2020, still the most of any state.[2]
Results
1852 United States presidential election in Vermont[3] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | Winfield Scott | 22,173 | 50.52% | 5 | |
Democratic | Franklin Pierce | 13,044 | 29.72% | 0 | |
Free Soil | John P. Hale | 8,621 | 19.64% | 0 | |
None | Write-ins | 52 | 0.12% | 0 | |
Totals | 43,890 | 100% | 5 |
See also
References
- ^ "1852 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "Will Vermont's 27-Cycle GOP Presidential Streak Ever Be Broken?". Smart Politics. April 30, 2012. Retrieved May 16, 2021.
- ^ "1852 Presidential General Election Results - Vermont". U.S. Election Atlas. David Leip. Retrieved March 17, 2017.