Talk:Inner regular measure
 | This article is rated Start-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | ||||||
| |||||||
Tight and Radon
The article states: since a finite measure μ is inner regular if and only if, for all ε > 0, there is some compact subset K of X such that μ(X \ K) < ε.
since a finite measure μ is inner regular if and only if, for all ε > 0, there is some compact subset K of X such that μ(X \ K) < ε.
I only know of a proof of this equivalence for metric spaces. Is it known to be true more generally? Logicdavid (talk) 13:49, 14 December 2023 (UTC)