1884 United States presidential election in Louisiana

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1884 United States presidential election in Louisiana

← 1880 November 4, 1884 1888 →
 
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 7 0
Popular vote 62,594 46,347
Percentage 57.22% 42.37%

Parish Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Louisiana took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.

Louisiana voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 14.85%.

Results

1884 United States presidential election in Louisiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York
Thomas Andrews Hendricks of Indiana
62,594 57.22% 8 100.00%
Republican
James Gillespie Blaine of Maine
John Alexander Logan of Illinois
46,347 42.37% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 338 0.31% 0 0.00%
Greenback
Benjamin Franklin Butler of Massachusetts
Absolom Madden West of Mississippi
120 0.11% 0 0.00%
Total 109,399 100.00% 8 100.00%

See also

References

  1. ^ "1884 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved November 25, 2020.