2014 Charles Sturt Adelaide International – Doubles

Samuel Groth and Matt Reid

Daniell and Jenkins won the title, defeating

Jose Rubin Statham in the final, 6–4, 6–4.^[1]

Seeds

First round					Quarterfinals					Semifinals					Final

1	M Reid J-P Smith	4	7	[10]
	Y Ito Shuichi Sekiguchi	6	5	[6]	1	M Reid J-P Smith	6	6
	B Mousley C Norrie	6	6			B Mousley C Norrie	1	2
	T Matsui D Udomchoke	3	4							1	M Reid J-P Smith	6⁷	7	[8]
3	J Statham	6⁴	6	[10]						3	J Statham	7⁹	5	[10]
	B Klahn M Krueger	7⁷	3	[8]	3	J Statham	6	3	[10]
	R Agar S Bader	4	4			T Ito H Moriya	3	6	[6]
	T Ito H Moriya	6	6												3	J Statham	4	4
WC	Simon Ede C O'Connell	4	4													M Daniell J Jenkins	6	6
	M Daniell J Jenkins	6	6			M Daniell J Jenkins	6	6
	M Banes Gavin van Peperzeel	5	6	[10]		M Banes G van Peperzeel	1	1
4	B Klein B Westerhof	7	4	[5]							M Daniell J Jenkins	6	6
WC	Darren K. Polkinghorne C Puttergill	6	1	[10]						2	A Bolt A Whittington	2	4
WC	Daniel Ferreti Aaron Leeder-Chard	4	6	[8]	WC	D Polkinghorne C Puttergill
	M Barton L Saville	2	3		2	A Bolt A Whittington	w/o
2	A Bolt A Whittington	6	6