Sereno del Mar, California

Coordinates: 38°23′01″N 123°04′23″W / 38.38361°N 123.07306°W / 38.38361; -123.07306
Source: Wikipedia, the free encyclopedia.

Sereno del Mar
UTC-7 (PDT)
GNIS feature ID2583134
U.S. Geological Survey Geographic Names Information System: Sereno del Mar, California

Sereno del Mar (Spanish for "Serene of the Sea") is a census-designated place (CDP) in Sonoma County, California.[2] Sereno del Mar sits at an elevation of 190 feet (58 m).[2] The 2020 United States census reported Sereno del Mar's population was 107.

Geography

According to the United States Census Bureau, the CDP covers an area of 0.7 square miles (1.9 km2), all of it land.

Demographics

The

Latino
of any race were 8 persons (6.3%).

The Census reported that 100% of the population lived in households.

There were 63 households, out of which 6 (9.5%) had children under the age of 18 living in them, 33 (52.4%) were

families
(58.7% of all households); the average family size was 2.32.

The population was spread out, with 9 people (7.1%) under the age of 18, 4 people (3.2%) aged 18 to 24, 22 people (17.5%) aged 25 to 44, 45 people (35.7%) aged 45 to 64, and 46 people (36.5%) who were 65 years of age or older. The median age was 59.3 years. For every 100 females, there were 100.0 males. For every 100 females age 18 and over, there were 91.8 males.

There were 115 housing units at an average density of 156.0 per square mile (60.2/km2), of which 85.7% were owner-occupied and 14.3% were occupied by renters. The homeowner vacancy rate was 3.6%; the rental vacancy rate was 18.2%. 85.7% of the population lived in owner-occupied housing units and 14.3% lived in rental housing units.

References

  1. ^ U.S. Census Archived 2011-02-20 at the Wayback Machine
  2. ^ a b c U.S. Geological Survey Geographic Names Information System: Sereno del Mar, California
  3. ^ "2010 Census Interactive Population Search: CA - Sereno del Mar CDP". U.S. Census Bureau. Archived from the original on July 15, 2014. Retrieved July 12, 2014.