2016 Connecticut Open – Doubles

Source: Wikipedia, the free encyclopedia.
Doubles
Kateryna Bondarenko
Chinese Taipei Chuang Chia-jung
Score7–5, 6–4
Details
Draw16
Seeds4
Events
Singles Doubles
← 2015 · Connecticut Open · 2017 →

Julia Görges and Lucie Hradecká were the defending champions, but chose not to participate this year.

Kateryna Bondarenko and Chuang Chia-jung
in the final, 7–5, 6–4

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 Hungary T Babos
Kazakhstan Y Shvedova
3 6 [10]
WC Poland K Jans-Ignacik
Denmark C Wozniacki
6 4 [8] 1 Hungary T Babos
Kazakhstan Y Shvedova
77 6
Germany A-L Grönefeld
Czech Republic K Peschke
6 6 Germany A-L Grönefeld
Czech Republic K Peschke
63 2
China C Liang
Poland A Rosolska
2 3 1 Hungary T Babos
Kazakhstan Y Shvedova
3 7 [7]
4 Spain A Medina Garrigues
Spain A Parra Santonja
0 1
K Bondarenko
Chinese Taipei C-j Chuang
6 5 [10]
K Bondarenko
Chinese Taipei C-j Chuang
6 6
K Bondarenko
Chinese Taipei C-j Chuang
7 1 [11]
WC Chinese Taipei S-w Hsieh
Germany A Petkovic
3 6 [10] WC Chinese Taipei S-w Hsieh
Germany A Petkovic
5 6 [9]
N Melichar
United States M Sanchez
6 1 [8]
K Bondarenko
Chinese Taipei C-j Chuang
5 4
Canada G Dabrowski
Spain MJ Martínez Sánchez
2 4 2 India S Mirza
Romania M Niculescu
7 6
J Larsson
6 6
J Larsson
5 63
Argentina M Irigoyen
Georgia (country) O Kalashnikova
0 4 3 Slovenia A Klepač
Slovenia K Srebotnik
7 77
3 Slovenia A Klepač
Slovenia K Srebotnik
6 6 3 Slovenia A Klepač
Slovenia K Srebotnik
6 3 [8]
D Jurak
Australia An Rodionova
7 6 2 India S Mirza
Romania M Niculescu
2 6 [10]
Spain L Arruabarrena
Switzerland X Knoll
5 4
D Jurak
Australia An Rodionova
1 4
WC
A Riske
0 3 2 India S Mirza
Romania M Niculescu
6 6
2 India S Mirza
Romania M Niculescu
6 6

References